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注册:2020-4-214
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发表于 2020-6-20 16:40:44 |只看该作者 |倒序浏览
本帖最后由 GeZebra 于 2020-6-20 16:41 编辑

以n78小区(SSB SCS=30kHz)为例,小区搜索中UE解调得到MIB, 假设MIB中定义的pdcch-ConfigSIB1=164,那么根据38.213表13-11, O=5, M=1;可计算得到:
对于SSB0:Type0-PDCCHCSS @ slot10/11 of every even SFN;
对于SSB1:Type0-PDCCHCSS @ slot11/12 of every odd SFN;
对于SSB2:Type0-PDCCHCSS @ slot12/13 of every
even SFN;
对于SSB3:Type0-PDCCHCSS @ slot13/14 of every odd SFN;
对于SSB4:Type0-PDCCHCSS @ slot14/15 of every
even SFN;
对于SSB5:Type0-PDCCHCSS @ slot15/16 of every odd SFN;
对于SSB6:Type0-PDCCHCSS @ slot16/17 of every
even SFN;
对于SSB7:Type0-PDCCHCSS @ slot17/18 of every odd SFN



按照电信2.5ms双周期的配置,此时slot4,8,9,14,18,19都是上行时隙;slot3,7,13,17是S时隙。从以上可见SSB3, SSB4, SSB7对应的Type0-PDCCHCSS落在上行slot.  而在未获得SIB1之前,UE并不清楚该小区的上下行配置。  



请教这种场景下(Type0-PDCCHCSS与UL slot重叠)gNB是如何处理的?








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