通信人家园

标题: GSM RACH比特位的产生  [查看完整版帖子] [打印本页]

时间:  2018-12-24 17:03
作者: snowsea     标题: GSM RACH比特位的产生

协议里说8位信息比特和6位校验比特,构成一个生成多项式,不知道5位校验比特怎么生成,用matlab怎么产生啊,求助大神!
The encoding of the access burst containing 8 information bits is defined as follows. It contains 8 information bits
d(0),d(1),...,d(7).  

Six parity bits p(0),p(1),...,p(5) are defined in such a way that in GF(2) the binary polynomial:
d(0)D13 +...+ d(7)D6 + p(0)D5 +...+ p(5), when divided by D6 + D5 + D3 + D2 + D + 1 yields a remainder equal
to D5 + D4 + D3 + D2 + D + 1.







通信人家园 (https://www.txrjy.com/) Powered by C114