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标题: 3GPP 38.521 终端测试规范里面关于RB allocation的问题  [查看完整版帖子] [打印本页]

时间:  2019-1-16 08:30
作者: pengbo902     标题: 3GPP 38.521 终端测试规范里面关于RB allocation的问题

本帖最后由 pengbo902 于 2019-1-16 08:30 编辑

如何理解3GPP 38.521-1中提及的RB allocation呢?

Edge_full_left: 2@0
Edge_full_right: 2@0
Edge_1RB_Left: 1@0
Edge_1RB_Right: 1@24
Inner_full: 12@6
Outer_full: 25@0
Inner_1RB_Right: 1@23
Inner_1RB_left: 1@1




时间:  2020-8-19 19:48
作者: rf_master_66



NRB is the maximum number of RBs for a given Channel bandwidth and sub-carrier spacing defined in Table 5.3.2-1.
RBStart,Low = max(1, floor(LCRB/2))
where max() indicates the largest value of all arguments and floor(x) is the greatest integer less than or equal to x.
RBStart,High = NRB – RBStart,Low – LCRB
The RB allocation is an Inner RB allocation if the following conditions are met:
RBStart,Low ≤ RBStart ≤ RBStart,High, and
LCRB ≤ ceil(NRB/2)
where ceil(x) is the smallest integer greater than or equal to x.
An Edge RB allocation is the one for which the RB(s) is (are) allocated at the lowermost or uppermost edge of the channel with LCRB ≤ 2 RBs.
The RB allocation is an Outer RB allocation for all other allocations which are not an Inner RB allocation or Edge RB allocation.

时间:  2021-8-25 17:39
作者: 拼命十三妹

请问楼主解决了没?我也有这个疑问
时间:  2024-3-4 16:39
作者: yubingz

举个例子,Edge_1RB_Right: 1@24就是1个RB从24开始
时间:  2024-3-7 13:47
作者: GBS

最终怎么解决




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